## Whiteboard Problem: Algebra

Below is a typical algebra problem. Keep in mind - word problems are tools to generate thought, not tasks to be completed.

Problem:

Water is being drained out of a tank through 2 pipes at the
rate of 330L/min. We know that one pipe releases 50L/min more than the other.
How much do the 2 pipes drain each?

Solution below if you want it - but remember, the joy is in
the struggle.

Solution:

Reasoning. If one pipe releases 50L/minute more than the
other then the difference between them is 50L/min. If I subtract the 50L/minute
from the higher capacity pipe, both pipes will be releasing the same quantity.
This will also remove 50L/m from the total. So together both release
280L/m. That means I halve 280 to get
140 for each pipe. Now we add 50L/m to one pipe bringing it to 190. So 140 plus
190 equals 330L/m.

This is harder to follow than actually do! Hope that makes
sense. A good activity would be to get
the learner (and you) write your own approach in your own words. Quite
difficult!

Algebra:

330= x+x+50

330= 2x + 50

Cancel 50 from both sides

280= 2x

x=140

140 + 50 = 190

You will discover that it is the written explanations that
make mathematics daunting. The concepts are actually pretty easy to grasp, it's
translating the concepts from other people that's the real challenge.

Or simpler, 330/2=165

ReplyDeletePipe one =165-25

Pipe two =165+25

Yes, that's probably the easier way - as one side increases the other decreases equally. I might try and find a more complex problem that has the same relationship.

ReplyDelete